Mathematics — All MCQs
1905 questions available
Q1381.Is 3200 divisible by?
Correct Answer: B
3200 ends in 00, so it is divisible by 2 (even), 5 (ends in 0), and 10 (ends in 0). Hence it is divisible by all three: 2, 5, 10.
Q1382.Two numbers are in the ratio 4:5 and their LCM is 180. What is the smallest of these two numbers?
Correct Answer: C
Let numbers be 4x and 5x. Their LCM is 20x = 180 => x = 9. The smaller number is 4 * 9 = 36.
Q1383.The ratio of A and B's ages is 6:5. After 5 years, it becomes 9:8. What is their age difference?
Correct Answer: D
Let ages be 6x and 5x. After 5 years: (6x+5)/(5x+5) = 9/8 => 48x+40 = 45x+45 => 3x=5 => x = 5/3. The constant age difference is 6x - 5x = x = 5/3 years.
Q1384.A and B work 7 hours/day. A completes a task in 6 days, B in 8 days. In how many days will they complete it together working 8 hours/day?
Correct Answer: B
A works 42 total hours, B works 56. Work rates per hour: A=1/42, B=1/56. Combined rate = 1/42 + 1/56 = 7/168 = 1/24. Working 8 hours/day, their daily output is 8 * 1/24 = 1/3. Total days = 3.
Q1385.An arithmetic progression has 2nd term = 20 and 8th term = 60. What is the 20th term?
Correct Answer: B
AP formula: T_n = a + (n-1)d. T_2 = a + d = 20. T_8 = a + 7d = 60. Difference: 6d = 40 => d = 20/3, and a = 40/3. T_20 = a + 19d = 40/3 + 380/3 = 420/3 = 140.
Q1386.Two numbers are in ratio 3 : 4 and their LCM is 240. What is the smaller of these two numbers?
Correct Answer: C
Let the numbers be 3x and 4x. Their LCM is 12x = 240 => x = 20. The smaller number is 3x = 3 * 20 = 60.
Q1387.Q is as much younger than R as he is older than T. If the sum of the ages of R and T is 50 years, what is the difference between R and Q's age?
Correct Answer: D
Q is younger than R by R - Q, and older than T by Q - T. R - Q = Q - T => R + T = 2Q. Sum of R and T is 50, so 2Q = 50 => Q = 25. Since individual ages of R and T are unknown, R - Q = 25 - T cannot be determined.
Q1388.What is 1/6 of 2460 km?
Correct Answer: A
Calculated as: 2460 * (1/6) = 2460 / 6 = 410 km.
Q1389.A train covers 240 km. If its speed is increased by 4 km/h, it takes 0.5 hours less. What is the original speed?
Correct Answer: B
Equation: 240/x - 240/(x+4) = 0.5. Simplifying: x² + 4x - 1920 = 0. Factoring: (x - 40)(x + 48) = 0. Since speed must be positive, x = 40 km/h.
Q1390.If the 3rd term of AP is 8 and 6th term of AP is 17, what is the 8th term of AP?
Correct Answer: B
T_3 = a + 2d = 8, T_6 = a + 5d = 17. Difference: 3d = 9 => d = 3. Finding first term: a + 6 = 8 => a = 2. 8th term: T_8 = a + 7d = 2 + 7(3) = 23.
Q1391.Solve the equation: 2√(x + 2) = 3√2. If x > 0, what is the value of x?
Correct Answer: A
Square both sides: 4(x + 2) = 18 => 4x + 8 = 18 => 4x = 10 => x = 2.5.
Q1392.What is the number if 40% of the number is 380?
Correct Answer: D
0.4 * x = 380 => x = 380 / 0.4 = 950.
Q1393.What is the average of 10 and 20?
Correct Answer: A
Calculated as: (10 + 20) / 2 = 30 / 2 = 15.
Q1394.What is the result of 15 × 6 ÷ 2?
Correct Answer: A
Following order of operations (left-to-right): 15 * 6 = 90. Then 90 / 2 = 45.
Q1395.Evaluate the expression: (1/25) × 100
Correct Answer: C
(1/25) * 100 = 100 / 25 = 4.
Q1396.If 3x = 12, what is the value of x?
Correct Answer: B
Divide both sides by 3: x = 12 / 3 = 4.
Q1397.If 6 men can dig a hole in 8 hours, how long will 4 men take to dig the same hole?
Correct Answer: A
Total work = 6 men * 8 hours = 48 man-hours. For 4 men: 48 man-hours / 4 men = 12 hours.
Q1398.Ali's age is double Anwar's age. In 6 years, the ratio of their ages will be 23:13. What is Ali’s current age?
Correct Answer: A
Let Anwar = x, Ali = 2x. After 6 years: (2x+6)/(x+6) = 23/13 => 26x + 78 = 23x + 138 => 3x = 60 => x = 20. Ali's age is 2x = 40 years.
Q1399.If A and B can do a work in 18 days, A and C in 12 days, and B and C in 9 days, how many days will B alone take?
Correct Answer: C
Rates: A+B=1/18, A+C=1/12, B+C=1/9. (A+B)+(B+C)-(A+C) = 2B = 1/18 + 1/9 - 1/12 = 2/36 + 4/36 - 3/36 = 3/36 = 1/12. Since 2B = 1/12, B's rate = 1/24. B alone takes 24 days.
Q1400.A school has classes of 10, 20, 30, and 40 students with pass percentages of 20%, 30%, 60%, and 100%. What is the pass percentage of the entire school?
Correct Answer: C
Passed students: (10*0.2) + (20*0.3) + (30*0.6) + (40*1.0) = 2 + 6 + 18 + 40 = 66. Total students = 10+20+30+40=100. Overall pass rate = 66/100 = 66%.